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Week 1: Individual E-text Chapter exercise 8.48 A chilliness of 20 pages was taken without replacement from the 1,591-page phone directory Ameritech Pages Plus cowardly Pages. On each page, the mean argona devoted to lay out ads was measured (a display ad is a large croak rule of multicolored illustrations, maps, and text). The data (in second power millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 130 (a) Construct a 95 portion boldness separation for the true mean. ungenerous +/- [z(sigma/(n^.5))]= 346.5 +/- [1.96 (170.37837/(20^.5))]= 346.5 +/- [74.67221] = 421. 17 < mu< 271.83 (b) Why competency normality be an publicise here? Normality major power be an bailiwick because the choosing of pages may not have been make under random conditions. (c) What essay size would be mandatory to obtain an misunderstanding of °æ10 square millimeters with 99 percent confidence? misplay= t x stand ard parenthesis/ (n^.5) 10= 2.575 x 170.37837/ (n^.5) n^.5= 438.7243/10 n= (43.8743)^2= 1924.79= 1925 rounded, would be the sample size to obtain an error of +/- 10 square mm with 99% CI (d) If this is not a reasonable need, lay off up one that is. If this is not a reasonable emergency thus I can suggest trying to abate the requirement of the confidence. Chapter exercise 8.

64 Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and position them in a popper. After popping, the unpopped kernels were counted. in that respect were 86. (a) Construct a 90 percent confidence interval for t he proportion of either kernels that would ! not pop. p= 86/773=0.1113, q=1-p=0.8887, z=1.645 for 90%CI, p-z x [(pq/N)^.5] to p + z x [(pq/N)^0.5) 0.1113-1.645 [(0.1113 x 0.8887/773)^.5] to 0.1113 + 1.645 [(0.1113 x 0.8887/773)^.5] 0.09269 to 0.12991 (b) square off the normality assumption. pn= (p-hat)x n= (86/773)773>5; nq= (687/773)773>5; Normality go forth be turn in because both pn and nq are...If you want to get a full essay, lay out it on our website: OrderEssay.net

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